If $-3+i x^2 y$ and $x^2+y+4 i$ are complex conjugates, then $\mathrm{x}=$

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Aicharya · Accepted Answer

$\because-3+\mathrm{ix}^2 \mathrm{y}$ and $\left(\mathrm{x}^2+\mathrm{y}+4 \mathrm{i}ight)$ are complex conjugate. Then, $-3-i x^2 y=x^2+y+4 i$ Comparing both sides we get:- $ \begin{aligned} & x^2+y=-3 ......(i)\ & -x^2 y=4.......(ii) \end{aligned} $ Solving eqs. (i) \& (ii), we get $ x= \pm 1 $

If $-3+i x^2 y$ and $x^2+y+4 i$ are complex conjugates, then $\mathrm{x}=$

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