If $|\bar{a}|=3,|\bar{b}|=5$ and $|\bar{c}|=7$ and $\bar{a}+\bar{b}+\bar{c}=\overline{0}$, then the angle…
If $|\bar{a}|=3,|\bar{b}|=5$ and $|\bar{c}|=7$ and $\bar{a}+\bar{b}+\bar{c}=\overline{0}$, then the angle between $\bar{a}$ and $\bar{b}$ is
- $\frac{\pi}{4}$
- $\frac{\pi}{2}$
- $\frac{\pi}{3}$
- $\frac{\pi}{6}$
Solution
$\begin{aligned} & \vec{a}+\vec{b}+\vec{c}=0 \\ & \Rightarrow \vec{a}+\vec{b}=-\vec{c} \\ & \Rightarrow|\vec{a}+\vec{b}|^2=|\vec{c}|^2 \\ & \Rightarrow|\vec{a}|^2+|\vec{b}|^2+2|\vec{a}||\vec{b}| \cos \theta=|\vec{c}|^2 \\ & \Rightarrow 3^2+5^2+2 \times 3 \times 5 \cos \theta=7^2 \\ & \Rightarrow \cos \theta=\frac{15}{30}=\frac{1}{2}=\cos \frac{\pi}{3} \\ & \Rightarrow \theta=\frac{\pi}{3}\end{aligned}$
Asked in: MHT CET 2022 (07 Aug Shift 2)
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