If $x^2+y^2-4 x-2 y+5=0$ and $x^2+y^2-6 x-4 y-3=$ 0 are members of a coaxial system of circles, then the…
If $x^2+y^2-4 x-2 y+5=0$ and $x^2+y^2-6 x-4 y-3=$ 0 are members of a coaxial system of circles, then the centre of a point circle in the system is
- $(-5,-6)$
- $(5,6)$
- $(3,5)$
- $(-8,-13)$
Solution
No solution. Refer to answer key.
Asked in: AP EAMCET 2015
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