If an iron (III) complex with the formula…

If an iron (III) complex with the formula \(\left[\mathrm{Fe}\left(\mathrm{NH}_3\right)_x(\mathrm{CN})_y\right]^{-}\)has no electron in its \(e_g\) orbital, then the value of \(x+y\) is
  1. 4
  2. 5
  3. 6
  4. 3

Solution

Complex is
$\begin{aligned} & x=2 \\ & y=4 \\ & \text { so } x+y=6\end{aligned}$

Asked in: JEE Main 2024 (04 Apr Shift 2)

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