If ambient temperature is 300 K , the rate of cooling at 600 K ts H . In the same surroundings, the rate of cooling at 900 K is

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Aicharya · Accepted Answer

$\mathrm{T}_0=300 \mathrm{~K}, \mathrm{~T}_1=600 \mathrm{~K}, \mathrm{~T}_2=900 \mathrm{~K}$ By stefan - Boltzmann law, Rate of cooling, $\mathrm{Q} \mu\left(\mathrm{T}^4-\mathrm{T}_0{ }^4ight)$ $\begin{aligned} & 	herefore \frac{\mathrm{Q}_2}{\mathrm{Q}}=\frac{\mathrm{T}_2^4-\mathrm{T}_0^4}{\mathrm{~T}_1^4-\mathrm{T}_0^4}=\frac{(900)^4-(300)^4}{(600)^4-(300)^4} \ & \Rightarrow \frac{\mathrm{Q}_2}{\mathrm{H}}=\frac{81-1}{16-1}=\frac{80}{15} \ & 	herefore \mathrm{Q}_2=\frac{16}{3} \mathrm{H} \end{aligned}$

If ambient temperature is 300 K , the rate of cooling at 600 K ts H . In the same surroundings, the rate of…

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