If a → = 2 i ^ + j ^ + 2 k ^ , then, the value of i ^ × a → × i ^ 2 + j ^ × a…

If a=2i^+j^+2k^, then, the value of i^×a×i^2+j^×a×j^2+k^×a×k^2, is equal to :

Solution

Let a=xi^+yj^+zk^, and using vector triple product, we have,
i^×a×i^=i^.i^a-i^.ai^=yj^+zk^
Similarly,

j^×a×j^=xi^+zk^

and k^×a×k^=xi^+yk^

Thus, 

i^×a×i^2+j^×a×j^2+k^×a×k^2
=yj^+zk^2+xi^+zk^2+xi^+yj^2

=2|a|2=2(9)=18

Asked in: JEE Main 2020 (04 Sep Shift 2)

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