Mathematics › Vectors › Product of 2 vectors
Given
a→=2i^+j^-3k^
b→=i^-2j^+k^
c→=-i^+j^-4k^
d¯=i^+j^+k^
Now,
a→×b→=i^j^k^21-31-21
=-5i^-5j^-5k^
c→×d→=i^j^k^-11-4111
=5i^+3j^-2k^
a→×b→×c→×d→=i^j^k^-5-5-553-2
=25i^-35j^+10k^
a→×b→×c→×d→=625+1225+100=1950=578
Asked in: AP EAMCET 2018 (25 Apr Shift 1)
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