If a + 2 b cos x ) ( a - 2 b cos y = a 2 - b 2 , where a > b > 0 , then d x d y at π 4 , π…

If a+2bcosx)(a-2bcosy=a2-b2, where a>b>0, thendxdy at π4,π4 is:
  1. a-2ba+2b
  2. a-ba+b
  3. a+ba-b
  4. 2a+b2a-b

Solution

a+2bcosxa2bcosy=a2b2

a2bcosy2bsinxdxdy+2bsinya+2bcosx=0

dxdy=2bsinya+2bcosx2bsinxa2bcosy=sinya+2bcosxsinxa2bcosy

dxdyπ4,π4=a+bab.

Asked in: JEE Main 2020 (04 Sep Shift 1)

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