If a = 2 ,   b = 3 , c = 4 in a triangle A B C , then cos C =

If a=2, b=3,c=4 in a triangle ABC, then cosC=
  1. 14
  2. -14
  3. 12
  4. -12

Solution

Given:

a=2, b=3, c=4

Now,

cosC=a2+b2-c22ab

⇒cosC=4+9-162×2×3

⇒cosC=-32×2×3

⇒cosC=-14

Asked in: AP EAMCET 2022 (04 Jul Shift 2)

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