If a > 0 and z = ( 1 + i ) 2 a - i , has magnitude 2 5 , then z - is equal to:

If a>0 and z=(1+i)2a-i , has magnitude 25 , then z- is equal to:
  1. -15-35i
  2. -35-15i
  3. 15-35i
  4. -15+35i

Solution

Z=1+i2a-i=2ia-i
z=252ia-i=2a2+1=25
a=3   a>0
So, z-=2i3-i-= -2i3+i=-2i3+i×3-i3-i
=-6i-232+1=-15-35i

Asked in: JEE Main 2019 (10 Apr Shift 1)

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