If a vessel containing a fluid of density \(\rho\) upto height \(h\) is accelerated vertically downwards…

If a vessel containing a fluid of density \(\rho\) upto height \(h\) is accelerated vertically downwards with acceleration \(a_0\). Then, the pressure by fluid at the bottom of vessel is given by the equation ........ ( \(p_0\) denotes the atmospheric pressure and \(g\) denotes the acceleration due to gravity).
  1. \(p=p_0+\rho g h+\rho h a_0\)
  2. \(p=p_0+\rho g h\)
  3. \(p=p_0+\rho h\left(g-a_0\right)\)
  4. \(p=p_0-\rho g h\)

Solution

When a vessel containing a fluid of density \(\rho\) upto height \(h\) is accelerated downwards with acceleration \(a_0\), then net gravitational acceleration acting on the fluid \(g^{\prime}=g-a_0\) ...(i) Hence, the pressure by the fluid at the bottom of vessel is given as \(p=p_0+\rho g^{\prime} h=p_0+\rho\left(g-a_0\right) h \text { [From Eq. (i)] }\)

Asked in: AP EAMCET 2020 (17 Sep Shift 1)

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