If a source is transmitting electromagnetic wave of frequency \(8.2 \times 10^6 \mathrm{~Hz}\), then…

If a source is transmitting electromagnetic wave of frequency \(8.2 \times 10^6 \mathrm{~Hz}\), then wavelength of the electromagnetic waves transmitted from the source will be
  1. \(36.5 \mathrm{~m}\)
  2. \(40.5 \mathrm{~m}\)
  3. \(42.3 \mathrm{~m}\)
  4. \(50.9 \mathrm{~m}\)

Solution

Frequency of electromagnetic wave, \(v=8.2 \times 10^6 \mathrm{~Hz}\) Wavelength, \(\lambda=\) ? We know that, velocity of electromagnetic wave is given as \(\begin{aligned} c & =\mathrm{v} \lambda \Rightarrow \lambda=\frac{c}{\mathrm{v}} \\ & =\frac{3 \times 10^8}{8.2 \times 10^6}=36.5 \mathrm{~m} \end{aligned}\)

Asked in: AP EAMCET 2020 (21 Sep Shift 1)

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