If a set of 30 games cards, 17 are white and rest are green. Out of 30,4 white and 5 green are marked…

If a set of 30 games cards, 17 are white and rest are green. Out of 30,4 white and 5 green are marked IMPORTANT. If a card is chosen randomly from this set, then possibility of choosing a green card or an 'IMPORTANT' card is
  1. $13 / 30$
  2. $22 / 30$
  3. $17 / 30$
  4. $9 / 13$

Solution

Total cards $=30$ Green cards $=30-17=13$ Important cards $=4+5=9$ 5 cards are green as well as IMPORTANT $\therefore$ Required probability $=\frac{13}{30}+\frac{9}{30}-\frac{5}{30}=\frac{17}{30}$

Asked in: AP EAMCET 2022 (07 Jul Shift 1)

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