If a line drawn from a fixed point M a ,   b cuts the circle x 2 + y 2 = k 2 at C and D , then M C…

If a line drawn from a fixed point Ma, b cuts the circle x2+y2=k2 at C and D, then MC×MD is equal to
  1. a2+b2+k2
  2. a2+b2-k2
  3. a2-b2-k2
  4. x2

Solution

Let the line have slope tanθ

x-acosθ=y-bsinθ=r

x=a+rcosθ, y=b+rsinθ

x2+y2=k2

a+rcosθ2+(b+rsinθ)2=k2

r2+2r(acosθ+bsinθ)+a2+b2-k2=0

It has two roots r1=MC and r2=MD

r1·r2=a2+b2-k2

MC×MD=a2+b2-k2

Asked in: AP EAMCET 2020 (23 Sep Shift 1)

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