If a hyperbola has length of its conjugate axis equal to 5 and the distance between its foci is 13 , then the eccentricity of the hyperbola is:

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Aicharya · Accepted Answer

$	herefore$ Conjugate axis $=5$ $	herefore 2 b=5$ Distance betwecn foci $=13$ $2 a e=13$ Then, $b^{2}=a^{2}\left(e^{2}-1ight)$ $\Rightarrow a^{2}=36$ $	herefore a=6$ $a e=\frac{13}{2} \Rightarrow e=\frac{13}{12}$

If a hyperbola has length of its conjugate axis equal to 5 and the distance between its foci is 13 , then…

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