If a function $f: R \rightarrow R$ is defined by $f(x)=\frac{4 x}{5}+3$, then $f^{-1}(x)=$

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Aicharya · Accepted Answer

Let $f(x)=\frac{4 x}{5}+3=y$ $	herefore 4 x=5 y-15 \Rightarrow x=\frac{5 y-15}{4}$ $	herefore f^{-1}(y)=\frac{5 y-15}{4} \Rightarrow f^{-1}(x)=\frac{5 x-15}{4}=\frac{5(x-3)}{4}$

If a function $f: R \rightarrow R$ is defined by $f(x)=\frac{4 x}{5}+3$, then $f^{-1}(x)=$

Solution