If a die is rolled three times, then the probability of getting a larger number on its face than the…
If a die is rolled three times, then the probability of getting a larger number on its face than the previous number each time, is
$\frac{15}{216}$
$\frac{5}{54}$
$\frac{13}{216}$
$\frac{1}{18}$
Solution
Here, total number of possible out come
$
=6^3=216
$
Now, we can choose any three numbers out of 6 numbers and we can place them in ascending order and we can place them in ascending order in only one way.
So, favourable out come $={ }^6 C_3=20$
Now, required probability $=\frac{20}{216}=\frac{5}{54}$