If a committee of 10 members is to be formed from 8 men and 6 women, then the number of different possible…
If a committee of 10 members is to be formed from 8 men and 6 women, then the number of different possible committees in which the men are in majority is
931
175
48
595
Solution
If men are in majority men can be $6,7,8$ in number Number of such ways
$={ }^8 C_6 \times{ }^6 C_4+{ }^8 C_7 \times{ }^6 C_3+{ }^8 C_8 \times{ }^6 C_2=595$