If a circle of a constant radius 6 passes through origin $O$ and meets the coordinate axes at $A$ and $B$,…
- $x^2+y^2=4$
- $x^2+y^2=36$
- $x^2+y^2=16$
- $x^2+y^2=6$
Solution

$\therefore \quad h=\frac{a}{3}$ and $k=\frac{b}{3}$ $a=3 h, b=3 k$ Now, $A B$ is diameter of circle. $\begin{aligned} \therefore & a^2+b^2=144 \\ \therefore & (3 h)^2+(3 k)^2=144 \Rightarrow h^2+k^2=\frac{144}{9}\end{aligned}$ $h^2+k^2=16$ $\therefore$ Locus of centroid of $\triangle O A B$ is $x^2+y^2=16$
Asked in: AP EAMCET 2021 (24 Aug Shift 2)