If A and B simultaneously toss one coin each every time, each 50 times, then the probability of not getting…
If A and B simultaneously toss one coin each every time, each 50 times, then the probability of not getting tail on both the coins is
$\left(\frac{3}{4}\right)^{50}$
$\left(\frac{2}{3}\right)^{50}$
$\left(\frac{1}{3}\right)^{50}$
d) $\left(\frac{1}{2}\right)^{50}$
Solution
$S=\{(T, T),(H, H),(T, H),(H, T)\}$.
Probability of not getting tail $=\frac{3}{4}$
$\therefore$ The required probability $=\left(\frac{3}{4}\right)^{50}$