If a and b are real numbers such that 2 + α 4 = a + b α , where α = - 1 + i 3 2 , then a + b…

If a and b are real numbers such that 2+α4=a+bα, where α=-1+i32, then a+b is equal to:
  1. 9
  2. 24
  3. 33
  4. 57

Solution

 2+α4=a+bα
4+α2+4α2=a+bα

Now using, α=-1+i322α+12=i32

α2=-1+α

So, a+bα=4-α-1+4α2

a+bα=3+3α2=91+2α+α2
a+bα=91+2α+-1-α=9α

a=0, b=9a+b=9

Asked in: JEE Main 2020 (04 Sep Shift 2)

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