If 75 % of a first order reaction was completed in 90 minutes, 60 % of the same reaction would be completed in approximately (in minutes) _____ (Take: log 2 = 0.30   ; log 2.5 = 0.40 )

Question

If 75 % of a first order reaction was completed in 90 minutes, 60 % of the same reaction would be completed in approximately (in minutes) _____ (Take: log 2 = 0.30 &#160; ; log 2.5 = 0.40 )

Aicharya · Accepted Answer

T = 2 .303 K &#8201; log &#8201; 100 100 &#8722; x % T 75 % = 2 .303 K &#8201; log &#8201; 100 25 = 90 T 60 % = 2 .303 K &#8201; log &#8201; 100 40 T 75 % T 60 % = 2 log 2 log 2 .5 &#8658; 90 T 60 % = 2 &#215; 0 .3 0 .4 T 60 % = 90 &#215; 4 6 = 60 &#8201; min .

If 75 % of a first order reaction was completed in 90 minutes, 60 % of the same reaction would be completed…

Solution