If 5 ampers of current is passed for 193 seconds through a solution containing Copper salt, $0.32…

If 5 ampers of current is passed for 193 seconds through a solution containing Copper salt, $0.32 \mathrm{~g}$ of copper is deposited. What is the oxidation state of the $\mathrm{Cu}$ in the salt?
  1. $+2$
  2. $+1$
  3. $+3$
  4. $+\frac{3}{2}$

Solution

Charges passing through solution $=5 \times 193=965 \mathrm{C}$ $\mathrm{Cu}^{\mathrm{n}+}+\mathrm{ne} \rightarrow \mathrm{Cu}$ $965 \mathrm{C}$ charge deposit $0.32 \mathrm{~g}$ $\begin{aligned} & \therefore \quad 96500 \mathrm{n} \text { C charge deposit }=\frac{0.32 \times 96500 \mathrm{n}}{965}=63.5 \\ & \therefore \mathrm{n} \simeq \frac{64}{32}=2\end{aligned}$

Asked in: AP EAMCET 2022 (08 Jul Shift 1)

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