If 2 is the length of a side of a triangle with its opposite angle ' $\pi / 3$ ', then the circumradius of…
- $\frac{2}{\sqrt{3}}$
- $\frac{4}{\sqrt{3}}$
- 2
- 4
Solution

$ \because \quad a=2 \text { and } \angle A=\frac{\pi}{3} $ So, by sine Iaw, we have $ \frac{a}{\sin A}=2 R \Rightarrow \frac{2}{\sqrt{3} / 2}=2 R \Rightarrow R=\frac{2}{\sqrt{3}} $
Asked in: AP EAMCET 2020 (22 Sep Shift 1)