If $\theta \in\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$, then $\cos ^{-1}(\sin \theta)$ is equal to

Question

Aicharya · Accepted Answer

$\begin{aligned} & \theta \in\left[-\frac{\pi}{2}, \frac{\pi}{2}\right], \cos ^{-1}(\sin \theta)=? \ & \Rightarrow \quad \cos ^{-1}\left[\cos \left(\frac{\pi}{2}-\theta\right)\right]=\left(\frac{\pi}{2}-\theta\right) \end{aligned}$

If \(\theta \in\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]\), then \(\cos ^{-1}(\sin \theta)\) is equal to

Solution