If 10 22 gas molecules each of mass 10 - 26 kg collides with a surface (perpendicular to it) elastically per second over an area 1   m 2 with a speed 10 4 m / s , the pressure exerted by the gas molecules will be of the order of:

Question

If 10 22 gas molecules each of mass 10 - 26 kg collides with a surface (perpendicular to it) elastically per second over an area 1 &#160; m 2 with a speed 10 4 m / s , the pressure exerted by the gas molecules will be of the order of:

Aicharya · Accepted Answer

Total momentum transferred in one second = n 2 m v = 10 22 2 × 10 - 26 × 10 4 = 2 Force experienced by surface = 2 N Pressure on surface = F o r c e A r e a = 2 1 = 2 P a

If 10 22 gas molecules each of mass 10 - 26 kg collides with a surface (perpendicular to it) elastically per…

Solution