Mathematics › Indefinite Integration › Integration by Substitution
∫0adx4+x2=π8
∫0adx22+x2=π8
Use,
∫dxa2+x2=1atan-1xa+c
⇒12tan-1a2=π8
⇒tan-1a2=π4
⇒a2=tanπ4
⇒a2=1
⇒a=2
Asked in: AP EAMCET 2021 (20 Aug Shift 1)
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