If ∫ 0 a d x 4 + x 2 = π 8 , then the value of a =

If 0adx4+x2=π8, then the value of a=
  1. 1
  2. 2
  3. 3
  4. 4

Solution

0adx4+x2=π8

0adx22+x2=π8

Use,

dxa2+x2=1atan-1xa+c

12tan-1a2=π8

tan-1a2=π4

a2=tanπ4

a2=1

a=2

Asked in: AP EAMCET 2021 (20 Aug Shift 1)

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