Mathematics › Definite Integration › Properties of Definite Integration
Given: ∫01 1-xnxmdx=k∫01 xn 1-xmdx
⇒I(m,n)=∫01 xm 1-xndx
⇒∫0a fxdx=∫0afa-xdx
⇒I(m,n)=∫01 1-xm 1-1-xndx
⇒I(m,n)=∫01 1-xm 1-1+xndx
⇒I(m,n)=∫01 1-xm xndx
⇒k=1
Asked in: AP EAMCET 2021 (20 Aug Shift 2)
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