Identify the reaction which does not liberate $\mathrm{N}_2$
Identify the reaction which does not liberate $\mathrm{N}_2$
- $\mathrm{NaN}_3 \underset{\Delta}{\longrightarrow}$ ?
- $\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7 \longrightarrow$ ?
- $\mathrm{NH}_4 \mathrm{Cl}+\mathrm{Ca}(\mathrm{OH})_2 \longrightarrow$ ?
- $\mathrm{Ba}\left(\mathrm{N}_3\right)_2 \longrightarrow$ ?
Solution
(a) $2 \mathrm{NaN}_3 \stackrel{\Delta}{\longrightarrow} 2 \mathrm{Na}+3 \mathrm{~N}_2$
(b) $\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7 \stackrel{\Delta}{\longrightarrow} \mathrm{Cr}_2 \mathrm{O}_3+\mathrm{N}_2+4 \mathrm{H}_2 \mathrm{O}$
(c) $2 \mathrm{NH}_4 \mathrm{Cl}+\mathrm{Ca}(\mathrm{OH})_2 \longrightarrow \mathrm{CaCl}_2+2 \mathrm{NH}_4 \mathrm{OH}$
(d) $\mathrm{Ba}\left(\mathrm{N}_3\right)_2 \longrightarrow \mathrm{Ba}+3 \mathrm{~N}_2$ Barium acide
Asked in: AP EAMCET 2018 (22 Apr Shift 1)
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