Identify the reaction taking place at anode during electrolysis of molten $\mathrm{NaCl}$ ?
- $2 \mathrm{OH}^{-} \rightarrow \mathrm{H}_2 \mathrm{O}+\frac{1}{2} \mathrm{O}_2+2 \mathrm{e}^{-}$
- $2 \mathrm{H}^{+} 2 \mathrm{e}^{-} \rightarrow \mathrm{H}_2$
- $\mathrm{Na}^{+}+\mathrm{le}^{-} \rightarrow \mathrm{Na}_{(\mathrm{s})}$
- $2 \mathrm{Cl}^{-} \rightarrow \mathrm{Cl}_{2(\mathrm{~g})}+2 \mathrm{e}^{-}$
Solution
Asked in: MHT CET 2022 (07 Aug Shift 1)