Identify the product obtained when benzamide is treated with bromine and aqueous sodium hydroxide?
Identify the product obtained when benzamide is treated with bromine and aqueous sodium hydroxide?
Bromobenzene
Phenol
Benzyl alcohol
Aniline
Solution
Aniline
When benzamide is treated with bromine and aqueous sodium hydroxide, an aniline with one fewer carbon atom than the original amide is formed.
Reaction involved is as follows:
The Hofmann bromamide/degradation reaction is the name for this reaction. Aniline $\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\right)$ will be the end product.
The Hofmann bromamide/degradation reaction is the name for this reaction. Aniline $\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\right)$ will be the end product.