Identify the product $X$ obtained in following reaction…

Identify the product $X$ obtained in following reaction $\mathrm{CH}_{3}-\left(\mathrm{CH}_{2}\right)_{4}-\mathrm{CH}_{3} \quad \frac{\mathrm{Cr}_{2} \mathrm{O}_{3}}{773 \mathrm{~K}, 10-20 \mathrm{~atm}} \mathrm{X}$
  1. $\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}+\mathrm{CH}_{2}=\mathrm{CH}_{2}+\mathrm{H}_{2}$
  2. $2 \mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}+\mathrm{H}_{2}$
  3. $\mathrm{C}_{6} \mathrm{H}_{6}+4 \mathrm{H}_{2}$
  4. $\mathrm{CH}_{3}-\left(\mathrm{CH}_{2}\right)_{3}-\mathrm{CH}=\mathrm{CH}_{2}+\mathrm{H}_{2}$

Solution

Higher alkane with more than 5 carbon atom undergoes cyclization to form benzene in presence of $\mathrm{Cr}_{2} \mathrm{O}_{3}$ under 10 to $20 \mathrm{~atm}$ pressure at $773 \mathrm{~K}$.

Asked in: MHT CET 2020 (13 Oct Shift 1)

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