Identify the pair of elements in which number of electrons in $(n-1)$ shell is same
Identify the pair of elements in which number of electrons in $(n-1)$ shell is same
- $\mathrm{Fe}, \mathrm{Mn}$
- $\mathrm{Zn}, \mathrm{Fe}$
- $\mathrm{K}, \mathrm{Sc}$
- $\mathrm{Mn}, \mathrm{Cr}$
Solution
1. Fe electronic configuration $=\left[\mathrm{Fe} \Rightarrow 1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^6 3 \mathrm{~s}^2\right.$ $\left.3 \mathrm{p}^6 4 \mathrm{~s}^2 3 \mathrm{~d}^6\right]$
Here $(n-1)$ shell is $3 d$ which have 6 electron.
2. mn electronic configuration $\left[\mathrm{Mn} \Rightarrow 1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^6 3 \mathrm{~s}^2\right.$ $\left.3 \mathrm{p}^6 4 \mathrm{~s}^2 3 \mathrm{~d}^5\right]$
( $\mathrm{n}-1$ ) shell have 5 electrons
3. Zn electronic configuration $\left[\mathrm{Zn} \Rightarrow 1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^6 3 \mathrm{~s}^2\right.$ $3 \mathrm{p}^6 4 \mathrm{~s}^2 3 \mathrm{~d}^{10}$ ]
[ $\mathrm{n}-1$ ) shell have 10 electron]
4. Sc electronic configuration $\left[\mathrm{Sc} \Rightarrow 1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^6 3 \mathrm{~s}^2 3 \mathrm{p}^6\right.$ $4 \mathrm{~s}^2 3 \mathrm{~d}^1$ ]
$(n-1)$ shell have 1 electron.
Kelectronic configuration is $\left[\mathrm{K} \Rightarrow 1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^6 3 \mathrm{~s}^2 3 \mathrm{p}^6 4 \mathrm{~s}^1\right]$ $(n-1)$ shell have 6 electron.
Cr electronic configuration is $\left[\mathrm{Cr} \Rightarrow 1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^6 3 \mathrm{~s}^2\right.$ $\left.3 p^6 4 s^1 3 d^5\right]$
Here $(n-1)$ shell have 5 electron.
So $\mathrm{Mn}, \mathrm{Cr}$ have same number of electron in $(\mathrm{n}-1)$ shell.
Asked in: AP EAMCET 2024 (20 May Shift 1)
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