Identify the order in which the spin only magnetic moment (in BM) increases for the following four ions
Identify the order in which the spin only magnetic moment (in BM) increases for the following four ions
I,II,IV,III
IV,I,II,III
III,IV,I,II
III,II,IV,I
Solution
Magnetic moment $(\mu)$ is given as
$\mu=\sqrt{n(n+2)}$
where, $n$ is number of unpaired electrons.
$\mathrm{Ti}^{2+}:[\mathrm{Ar}] 3 d^2 ;$ number of unpaired electrons $=2$
$\mathrm{Cu}^{2+}:[\mathrm{Ar}] 3 d^9 ;$ number of unpaired electrons $=1$
$\mathrm{V}^{2+}:[\mathrm{Ar}] 3 d^3$; number of unpaired electrons $=3$
Hence, the increasing order of magnetic moment is as
$\mathrm{Cu}^{2+} < \mathrm{Ti}^{2+} < \mathrm{V}^{2+} < \mathrm{Fe}^{2+} .$
