Identify the number of unpaired electrons present and geometry respectively of…
Identify the number of unpaired electrons present and geometry respectively of $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ complex.
0 , square planar
2, square planar
4, octahedral
0 , octahedral
Solution
$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$
Oxidation state of $\mathrm{Co}=+3$
Electronic configuration of $\mathrm{Co}^{+3}=[\mathrm{Ar}] 3 \mathrm{~d}^6 4 \mathrm{~s}^{\circ}$
$\mathrm{NH}_3$ is strong field ligand. Pairing will take place. No. of unpaired electrons $=0$. Geometry: Octahedral