Identify the number of unpaired electrons present and geometry respectively of…

Identify the number of unpaired electrons present and geometry respectively of $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ complex.
  1. 0 , square planar
  2. 2, square planar
  3. 4, octahedral
  4. 0 , octahedral

Solution

$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ Oxidation state of $\mathrm{Co}=+3$ Electronic configuration of $\mathrm{Co}^{+3}=[\mathrm{Ar}] 3 \mathrm{~d}^6 4 \mathrm{~s}^{\circ}$ $\mathrm{NH}_3$ is strong field ligand. Pairing will take place. No. of unpaired electrons $=0$. Geometry: Octahedral

Asked in: MHT CET 2021 (23 Sep Shift 2)

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