Identify the major product formed in the bromination of 2-Methylpropane.
- 1-Bromopropane
- 2-Bromopropane
- 1-Bromo-2-methylpropane
- 2-Bromo-2-methylpropane
Solution

This is because the intermediate formed is $3^{\circ}$ alkyl radical which is more stable than $1^{\circ}$ alkyl radical.
Asked in: MHT CET 2024 (10 May Shift 2)