Identify the element reduced in following reaction. $\mathrm{Cr}_2 \mathrm{O}_7^{2-}+14 \mathrm{H}^{+}+6…
- Cr
- H
- 0
- I
Solution

In the following redox reaction, $I^{-}$is getting oxidized (change in O.S. from -1 to 0 ) and Cr is getting reduced (change in O.S. from +6 to +3 ).
Asked in: MHT CET 2024 (03 May Shift 1)