Identify the element reduced in following reaction. $\mathrm{Cr}_2 \mathrm{O}_7^{2-}+14 \mathrm{H}^{+}+6…

Identify the element reduced in following reaction. $\mathrm{Cr}_2 \mathrm{O}_7^{2-}+14 \mathrm{H}^{+}+6 \mathrm{I}^{-} \longrightarrow 2 \mathrm{Cr}^{3+}+3 \mathrm{H}_2 \mathrm{O}+3 \mathrm{I}_2$
  1. Cr
  2. H
  3. 0
  4. I

Solution


In the following redox reaction, $I^{-}$is getting oxidized (change in O.S. from -1 to 0 ) and Cr is getting reduced (change in O.S. from +6 to +3 ).

Asked in: MHT CET 2024 (03 May Shift 1)

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