Identify the correct trend given below: (Atomic No. = Ti : 22, Cr : 24 and Mo : 42)

Identify the correct trend given below:

(Atomic No. = Ti : 22, Cr : 24 and Mo : 42)
  1.  of CrH2O62+>MoH2O62+ and  of TiH2O63+>TiH2O62+
  2.  of CrH2O62+>MoH2O62+ and  of TiH2O63+<TiH2O62+
  3.  of CrH2O62+<MoH2O62+ and  of TiH2O63+>TiH2O62+
  4.  of CrH2O62+<MoH2O62+ and  of TiH2O63+<TiH2O62+

Solution

As the oxidation state of metal increases the CFSE value increases hence  Δof [Ti(H2O)6]3+>[Ti(H2O)6]2+

  Δ increase from 3d to 4d Series. So,   

Δ CFSE (Crystal field stabilisation energy)

Δ of CrH2O62+<Δ of MoH2O62+

Because here Δ depends on Zeff & Zeff of 4d series is more than 3d series  

 

Asked in: JEE Main 2016 (09 Apr Online)

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