Identify the correct statements from the following I. $\mathrm{B}_2 \mathrm{H}_6$ is an electron deficient…
- I, II, III
- II, III, IV
- I, II, IV
- I, III, IV
Solution

$3 \mathrm{C}-2 e^{-}$electron deficient bridge bond (II) $\mathrm{NH}_3$ is electron rich hydride due to presence of lone pair of electrons.

(III) $\mathrm{NaH}$ is an ionic hydride, generally hydride of alkali metals are ionic. Hence, statement III is incorrect. (IV) $\mathrm{YbH}_{2.55}$ is an interstitial hydride. Here, smaller atom like hydrogen present in interstitial space of $\mathrm{Yb}$ metal. Hence, it forms interstitial hydride. Thus, option (c) is correct.
Asked in: AP EAMCET 2019 (20 Apr Shift 2)
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