Identify the correct relation between depression in freezing point and freezing point of pure solvent?

Identify the correct relation between depression in freezing point and freezing point of pure solvent?
  1. $\mathrm{T}^{\circ}=\mathrm{T} \times \Delta \mathrm{T}_{\mathrm{f}}$
  2. $\mathrm{T}^{\circ}=\Delta \mathrm{T}_{\mathrm{f}}-\mathrm{T}$
  3. $\mathrm{T}^{\circ}=\mathrm{T}-\Delta \mathrm{T}_{\mathrm{f}}$
  4. $\mathrm{T}^{\circ}=\Delta \mathrm{T}_{\mathrm{f}}+\mathrm{T}$

Solution

$\Delta T_{f}=T^{0}-T$ $\therefore T^{0}=\Delta T_{f}+T$ $T^{0}=$ freezing point of pure solvent $T=$ freezing point of solution $\Delta T_{f}=$ depression in freezing point

Asked in: MHT CET 2020 (15 Oct Shift 2)

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