Identify the correct order of acidic strength of $\mathrm{CO}_{2}, \mathrm{CuO}, \mathrm{CaO},…
- $\mathrm{CaO} < \mathrm{CuO} < \mathrm{H}_{2} \mathrm{O} < \mathrm{CO}_{2}$
- $\mathrm{H}_{2} \mathrm{O} < \mathrm{CuO} < \mathrm{CaO} < \mathrm{CO}_{2}$
- $\mathrm{CaO} < \mathrm{H}_{2} \mathrm{O} < \mathrm{CuO} < \mathrm{CO}_{2}$
- $\mathrm{H}_{2} \mathrm{O} < \mathrm{CO}_{2} < \mathrm{CaO} < \mathrm{CuO}$
Solution
$\mathrm{CaO} \longrightarrow$ basic, $\mathrm{H}_{2} \mathrm{O} \longrightarrow$ neutral So, correct order of acidic strength is $\mathrm{CaO} < \mathrm{CuO} < \mathrm{H}_{2} \mathrm{O} < \mathrm{CO}_{2}$ *
Asked in: JEE-TOPICTESTS-CHEMISTRY
Practice more CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES questions on Aicharya