Identify the correct order in which the covalent radius of the following elements increases (I)…
Identify the correct order in which the covalent radius of the following elements increases
(I) $\mathrm{Ti}$$\quad$(II) $\mathrm{Ca}$$\quad$(III) Sc
- (I), $\quad$ (II), $\quad$ (III)
- (III), $\quad$ (II), $\quad$ (I)
- $\begin{array}{lll}(\mathrm{II}), & \text { (I) }, \quad \text { (III) }\end{array}$
- (I), $\quad$(III), $\quad$(II)
Solution
$\begin{aligned}
& { }_{20} \mathrm{Ca}=[\mathrm{Ar}] 4 s^2 \\
& { }_{21} \mathrm{Sc}=[\mathrm{Ar}] 4 s^2, 3 d^1 \\
& { }_{22} \mathrm{Ti}=[\mathrm{Ar}] 4 s^2, 3 d^2
\end{aligned}$
As $d$-orbital have diffused shape, hence their electron shields nuclear charge upto lesser extent. Hence, due to increase in effective nuclear charge $\left(Z_{\text {eff }}\right)$, atomic size decrease, in the following order,
$\mathrm{Ca}>\mathrm{Sc}>\mathrm{Ti}$
Asked in: AP EAMCET 2005
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