Identify the compound formed from elements $\mathrm{X}, \mathrm{Y}, \mathrm{Z}$ having oxidation state $+2…

Identify the compound formed from elements $\mathrm{X}, \mathrm{Y}, \mathrm{Z}$ having oxidation state $+2,+5,-2$ respectively.
  1. $\mathrm{X}\left(\mathrm{Y}_4 \mathrm{Z}\right)$
  2. $\mathrm{X}_3\left(\mathrm{YZ}_4\right)_2$
  3. $\mathrm{X}_3\left(\mathrm{YZ}_2\right)_2$
  4. $\mathrm{XYZ}_2$

Solution

$\begin{array}{lll} \mathrm{X}^{+2} & \mathrm{Y}^{+5} & \mathrm{Z}^{-2} \end{array}$ Overall charge on compound formed by elements X. Y and $\mathrm{Z}$ should be zero. $\begin{aligned} & \mathrm{X}_3\left(\mathrm{YZ}_4\right)_2 \Rightarrow 3 \times 2+2 \times 5+8 \times(-2)=0 \\ & \mathrm{X}\left(\mathrm{Y}_4 \mathrm{Z}\right) \Rightarrow 1 \times 2+4 \times 5+1 \times(-2) \neq 0 \\ & \mathrm{X}_3\left(\mathrm{YZ}_2\right)_2 \Rightarrow 3 \times 2+2 \times 5+4 \times(-2) \neq 0 \\ & \mathrm{XYZ}_2 \Rightarrow 1 \times 2+1 \times 5+2 \times(-2) \neq 0 \end{aligned}$

Asked in: MHT CET 2021 (24 Sep Shift 1)

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