$ \mathrm{C}_6 \mathrm{H}_5-\mathrm{O}-\mathrm{CH}_2 \mathrm{CH}_3…

$ \mathrm{C}_6 \mathrm{H}_5-\mathrm{O}-\mathrm{CH}_2 \mathrm{CH}_3 \underset{\Delta}{\stackrel{\mathrm{HI}}{\longrightarrow}} Y+Z $ Identify $Y$ and $Z$ in the above reaction. $\begin{array}{l|l} X & Y \end{array}$
  1. $ \begin{array}{l|l} C_{6}H_{5}OH & H_{3}CCH_{3} \end{array} $
  2. $\begin{aligned}C_{2}H_{5}I | C_{6}H_{5}CHO\end{aligned}$
  3. $ \begin{array}{l|l} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{I} & \mathrm{H}_{3} \mathrm{CCH}_{2} \mathrm{OH} \end{array} $
  4. $C_{6}H_{5}OH \quad H_{3}CCH_{2}$

Solution

When an alkyl aryl ether is reacted with halogen acid $(H X)$, the products are always phenol and an alkyl halide. $ \begin{aligned} \mathrm{C}_6 \mathrm{H}_5-\mathrm{O}-\mathrm{CH}_2- & \mathrm{CH}_3+\mathrm{HI} \stackrel{100 \mathrm{C}}{\longrightarrow} \\ & \mathrm{C}_6 \mathrm{H}_5 \mathrm{OH}+\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{I} \end{aligned} $

Asked in: AP EAMCET 2014

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