' $n$ ' identical cells each of emf $E$ and internal resistance ' $r$ ' are joined in series to form a row.…

' $n$ ' identical cells each of emf $E$ and internal resistance ' $r$ ' are joined in series to form a row. ' $m$ ' such rows are joined in parallel across a load resistance $R$. The current in each cell is
  1. $\begin{aligned} & \frac{\mathrm{nE}}{\mathrm{nr}} \mathrm{m}+\mathrm{R}\end{aligned}$
  2. $\begin{aligned} & \frac{\mathrm{nE}}{\mathrm{nr}+\mathrm{mR}} \end{aligned}$
  3. $\begin{aligned} & \frac{\mathrm{mE}}{\frac{\mathrm{mr}}{\mathrm{n}}+\mathrm{R}}\end{aligned}$
  4. $\begin{aligned} & \frac{\mathrm{E}}{\frac{\mathrm{nr}}{\mathrm{m}}+\mathrm{R}}\end{aligned}$

Solution

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Asked in: AP EAMCET 2017 (26 Apr Shift 2)

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