Hyperconjugation is not observed in

1. $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2$
2. 
3. 
4. $\mathrm{CH}_2=\mathrm{CH}_2$

Solution

For hyperconjugation, $\alpha \mathrm{H}$ must be present w.r.t double bond $(=)$, +ve radical.

Asked in: MHT CET 2022 (10 Aug Shift 1)

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