Hydrolysis of $\mathrm{XeF}_4$ gives $\mathrm{HF}, \mathrm{O}_2, \mathrm{Xe}$ and ' X '. The structure of '…
Hydrolysis of $\mathrm{XeF}_4$ gives $\mathrm{HF}, \mathrm{O}_2, \mathrm{Xe}$ and ' X '. The structure of ' X ' is
- pyramidal
- Square pyramidal
- octahedral
- Square planar
Solution
$6 \mathrm{XeF}_4+12 \mathrm{H}_2 \mathrm{O} \longrightarrow 4 \mathrm{Xe}+2 \mathrm{XeO}_3+24 \mathrm{HF}+3 \mathrm{O}_2$
Asked in: AP EAMCET 2024 (23 May Shift 1)
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