Hydrogen atom is excited from ground state to another state with principal quantum number equal to $4$. Then…
Hydrogen atom is excited from ground state to another state with principal quantum number equal to $4$. Then the number of spectral lines in the emission spectra will be
$2$
$3$
$5$
$6$
Solution
Number of spectral lines from a state $\mathrm{n}$ to ground state is
$=\frac{n(n-1)}{2}=6.$