Hydroboration oxidation and acid hydration will not give the same products in case of

1. 
2. 
3. $\mathrm{CH}_{2}=\mathrm{CH}_{2}$
4. $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}$

Solution

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Asked in: JEE-TOPICTESTS-CHEMISTRY

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