Hybridization of positively charged and negatively charged carbons of the following respectively are
Hybridization of positively charged and negatively charged carbons of the following respectively are
$\mathrm{sp}^2, \mathrm{sp}$
$\mathrm{sp}^2, \mathrm{sp}^2$
$\mathrm{sp}^3, \mathrm{sp}^3$
$\mathrm{sp}^3, \mathrm{sp}^2$
Solution
Positively- charged carbon in carbocation $=\mathrm{sp}^2$ - hybridized due to three bond pairs and zero lone pairs.
Negatively - charged carbon in carbanion $=s p-$ hybridized due to one lone pair and one bond pair of electrons.
